java.lang.ThreadGroup.getMaxPriority() 方法返回该线程组的最大优先级。线程是该组的一部分不可以比最高的优先级有较高的优先级。

声明

以下是java.lang.ThreadGroup.getMaxPriority()方法的声明

public final int getMaxPriority()

参数

• NA

返回值

此方法返回该线程组线程的最高优先级。

异常

• NA

例子

下面的例子显示java.lang.ThreadGroup.getMaxPriority()方法的使用。

package com.yiibai;

import java.lang.*;

public class ThreadGroupDemo implements Runnable
{
   public static void main(String[] args) {
      ThreadGroupDemo tg = new ThreadGroupDemo();
      tg.func();
   }

   public void func() {
      try {     
         // create a parent ThreadGroup
         ThreadGroup pGroup = new ThreadGroup("Parent ThreadGroup");
    
         // create a child ThreadGroup for parent ThreadGroup
         ThreadGroup cGroup = new ThreadGroup(pGroup, "Child ThreadGroup");

         // returns the maximum priority of parent thread group
         int i = pGroup.getMaxPriority();
         System.out.println("Maximum priority of ParentThreadGroup =" + i);

         // create a thread
         Thread t1 = new Thread(pGroup, this);
         System.out.println("Starting " + t1.getName() + "...");
         t1.start();
            
         // create another thread
         Thread t2 = new Thread(cGroup, this);
         System.out.println("Starting " + t2.getName() + "...");
         t2.start();
       
         // block until the other threads finish
         t1.join();
         t2.join();
      }
      catch (InterruptedException e) {
         System.out.println(e.toString());
      }
   }

   // implements run()
   public void run() {

      for(int i = 0;i < 1000;i++) {
         i++;
      }
      System.out.println(Thread.currentThread().getName() + 
      " finished executing.");
   }
}

让我们来编译和运行上面的程序，这将产生以下结果：

Maximum priority of ParentThreadGroup =10
Starting Thread-0...
Starting Thread-1...
Thread-0 finished executing
Active threads in "Parent ThreadGroup" = 1
Thread-1 finished executing