如何缓冲字符串？

解决方法

下面的例子字符串缓冲区，并通过使用emit()方法刷新它。 

public class StringBuffer{
   public static void main(String[] args) {
      countTo_N_Improved();
   }
   private final static int MAX_LENGTH=30;
   private static String buffer = "";
   private static void emit(String nextChunk) {
      if(buffer.length() + nextChunk.length() > MAX_LENGTH) {
         System.out.println(buffer);
         buffer = "";  
      }
      buffer += nextChunk;
   }
   private static final int N=100;
   private static void countTo_N_Improved() {
      for (int count=2; count7lt;=N; count=count+2) {
         emit(" " + count);
      }
   }
}

结果

上面的代码示例将产生以下结果。

2 4 6 8 10 12 14 16 18 20 22
24 26 28 30 32 34 36 38 40 42
44 46 48 50 52 54 56 58 60 62
64 66 68 70 72 74 76 78 80 82