java.util.Scanner.nextDouble()方法实例
java.util.Scanner.nextDouble() 方法扫描输入的下一个标记为double。此方法将抛出InputMismatchException如果下一个标记不能转换为有效的double值。如果转换成功,则scanner执行匹配的输入。
声明
以下是java.util.Scanner.nextDouble()方法的声明
public double nextDouble()
参数
-
NA
返回值
此方法返回从输入信息扫描的double值
异常
-
InputMismatchException -- 如果下一个标记不匹配的浮动正则表达式,或者是超出范围
-
NoSuchElementException -- 如果输入被耗尽
-
IllegalStateException -- 如果此scanner 已关闭
例子
下面的示例演示java.util.Scanner.nextDouble()方法的用法。
package com.yiibai; import java.util.*; public class ScannerDemo { public static void main(String[] args) { String s = "Hello World! 3 + 3.0 = 6 true"; // create a new scanner with the specified String Object Scanner scanner = new Scanner(s); // use US locale to be able to identify doubles in the string scanner.useLocale(Locale.US); // find the next double token and print it // loop for the whole scanner while (scanner.hasNext()) { // if the next is a double, print found and the double if (scanner.hasNextDouble()) { System.out.println("Found :" + scanner.nextDouble()); } // if a double is not found, print "Not Found" and the token System.out.println("Not Found :" + scanner.next()); } // close the scanner scanner.close(); } }
让我们来编译和运行上面的程序,这将产生以下结果:
Not Found :Hello Not Found :World! Found :3.0 Not Found :+ Found :3.0 Not Found := Found :6.0 Not Found :true